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A rod of finite length having linear charge density subtends an angle of 15^ at a point P which is also the centre of curvature of a circular arc having same linear charge density as shown in figure. If the net electric field at the origin is b K R . Find the value of b :

Correct answer

0

Step-by-step solution

formula for rod and are both are k d ( + ) i + k d ( - ) j So, E = 0 and b=0

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