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A charge +Q is located somewhere inside a vertical cone such that the depth of the charge from the free surface of the cone is H . It is found that the flux associated with the cone with the curved surface is 3 Q 5 ₀ . If the charge is raised vertically through a height 2 H , the flux associated with the cone with the curved surface is Q 20 ₀ . What should be the value of ?

Correct answer

8

Step-by-step solution

If we place another similar cone on this one, net flux = Q ₀ Flux with the upper cone = Q ₀ - 3 Q 5 ₀ = 2 Q 5 ₀ = 8 Q 20 ₀ . This must also be the flux associated with the lower cone when the charge is raised through a height 2 H because of symmetry.

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