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Most Important Selected Qs for JEE AdvancedPhysicsMagnetic Effects of Current

A non conducting non-magnetic rod having square crosssection of side L / 4 is suspended from a rigid support as shown in the figure. A light and small coil of 600 turns is wrapped tightly at the left end of the rod where uniform magnetic field B exists in vertically downward direction. Air of density hits the half of the right part of the rod with velocity v as shown in the figure. What should be the current (in mA )

Correct answer

525

Step-by-step solution

For the rod to remain horizontal, _ net =0 _ air = ( L 4 L 2 ) v v 3 L 4 ; _ mag = B =N i ( L 4 )^2 B I= _ air N B ( L 4 )^2

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