For the arrangement shown in the figure. The time interval in seconds after which the water jet ceases to cross the wall is found to be (A)^3 . Area of the cross section of the tank A= 5 ~m ^2 and area of the orifice a=32 ~cm ^2 . [Assume that the container remaining fixed]. Find the value of . (Take g=10 ~m / s ^2 )

Step-by-step solution

For minimum velocity at orifice ( v _ ) 2 ~h ~g =1 v _ = 5 ~m / s This will give us minimum height for this velocity aligned & 2 g h_ mh = 5 h_ = 1 4 ~m =0.25 ~m & v ₁= 2 gh & v ₂=- dh / dt aligned By equation of continuity av ₁= Av ₂ aligned & a 2 gh = A (- dh dt ) _ 0.81 ^ 0.25 dh ~h = ₀^ t ( a 2 ~g ) A dt & t =125 sec =(5)^3=( A )^3 =5 aligned