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Most Important Selected Qs for JEE AdvancedPhysicsMotion in Two Dimensions

Two particles P and Q are launched simultaneously as shown in figure. Find the minimum distance between particles in meters.

Correct answer

6

Step-by-step solution

v _ P Q = v _P- v _Q= ( 10 2 i + 10 2 j )- (- 70 2 i + 70 2 j )=40 2 i -30 2 j AB =90 4 3 =120 ~m P QB =10 ~m P QM =10 37^ =10 3 5 =6 ~m

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