Most Important Selected Qs for JEE AdvancedPhysicsMotion in Two Dimensions
A particle is projected from ground towards a vertical wall 80 m away at an angle of 37^ with horizontal with initial velocity of 50 ~m / s . After its collision with wall & then once with ground find at what distance in meter from wall will it strike the ground. The component of velocity normal to the surface becomes half after collision with each surface.
Correct answer
140
Step-by-step solution
After first collision : v _ y =30- gt ; v _ x =-20 i ; t₁= 80 40 =2 sec ; t ₂= T - t ₁=4 sec Before second collision : v_x=-20 i ; x =20 4=-80 ~m ; v _ y =10-10 ( t ₂ )=-30 j After second collision : v_x=-20 i ; v_y=+15 j Range =60 ~m Net: 60 ~m +80 ~m =140 ~m