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Most Important Selected Qs for JEE AdvancedChemistryIonic Equilibrium

Paragraph: A solution is 0.1 M in each KCl , KBr and K ₂ CrO ₄ . To this solution solid AgNO ₃ is gradually added. Assume no change in the volume of the solution. aligned & Given K _ sp ( AgCl )=1.7 10⁻¹⁰ & ~K _ sp ( AgBr )=5 10⁻¹³ & and _ spp ( Ag ₂ CrO ₄ )=1.9 10⁻¹² aligned Question: The sequence of ions precipitated follows the order?

Options

  1. ACl ⁻, Br ⁻, CrO ₄²⁻
  2. BBr ⁻, Cl ⁻, CrO ₄²⁻
  3. CCl ⁻, CrO ₄²⁻, Br ⁻
  4. DCrO ₄²⁻, Cl ⁻, Br ⁻

Correct answer

B. Br ⁻, Cl ⁻, CrO ₄²⁻

Step-by-step solution

[ Ag ⁺ ] to start the ppt. of Cl ⁻= K _ sp ( AgCl ) [ Cl ⁻ ] = 1.7 10⁻¹⁰ 0.1 =1.7 10⁻⁹ M [ Ag ⁺ ] to start the ppt. of Br ⁻= K _ sp ( AgBr ) [ Br ⁻ ] = 5 10⁻¹³ 0.1 =5 10⁻¹² M [ Ag ⁺ ] to start the ppt. of CrO ₄²⁻= [ K _ sp ( Ag ₂ CrO ₄ ) [ CrO ₄²⁻ ] ]^ 1 / 2 = [ 1.9 10⁻¹² 0.1 ]^ 1 / 2 =4.36 10⁻⁶ M Order of ppt. Br ⁻, Cl ⁻, CrO ₄²⁻ .

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