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Most Important Selected Qs for JEE AdvancedMathematicsCircle

Paragraph: Consider the two points A (3,7) and B (6,5) . Family of circles S is drawn passing through these two points. A circle C is also given whose equation is x ^2+ y ^2-4 x -6 y -3=0 . On the basis of above information answer the following : Question: Equation of the member of the family S which bisects the circumference of C is -

Options

  1. Ax^2+y^2-5 x+6 y-1=0
  2. Bx^2+y^2-5 x+6 y+1=0
  3. Cx^2+y^2-5 x-6 y-1=0
  4. Dx^2+y^2+5 x-6 y+1=0

Correct answer

C. x^2+y^2-5 x-6 y-1=0

Step-by-step solution

Centre (2,3) will lie on the common chord so -28+14 =0 =2 so equation of required circle will be x^2+y^2-5 x-6 y-1=0

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