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Paragraph: Let a, b, c, d R . Then the cubic equation of the type a x^3+b x^2+c x+d=0 has either one root real or all three roots are real. But in case of trigonometric equations of the type a ^3 x+b ^2 x+c x+d=0 can possess several solutions depending upon the domain of x . To solve an equation of the type a +b =c . The equation can be written as ( - )=c / (a^2+b^2 ) . The solution is =2 n + , where tan =b / a, =c /

Options

  1. AOnly one real root
  2. BThree real roots
  3. CFour real roots
  4. DSix real roots

Correct answer

D. Six real roots

Step-by-step solution

4 ^3 x+2 ^2 x-2 x-1=(2 x+1) (2 ^2 x-1 )=0 x=- 1 2 , 1 2 There are 6 solutions.

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