Most Important Selected Qs for JEE AdvancedPhysicsElectrostatics
Paragraph: A uniform disc of mass m and radius R is made up of two halves, one half has charge +Q uniformly distributed over it & another half has charge -Q uniformly distributed over it. This system is kept on rough surface in a uniform horizonal field E in a way so that line of seperation become parallel to field, system is released from rest, at t =0 as shown in figure. Question: Minimum value of coefficient of fr
Options
- A4 QE 9 mg
- B8 QE 9 mg
- C16 QE 9 mg
- D2 QE 3 mg
Correct answer
C. 16 QE 9 mg
Step-by-step solution
F _ r = ma = m ( 16 QE 9 ~m )= 16 QE 9 ~F _ r = N = mg 16 QE 9 = mg = 16 QE 9 mg