Paragraph: The electric field intensity at all points in space is given by E = 3 i - j volts/metre. A square frame LMNO of side 1 metre is shown in figure. The point N lies in x - y plane. The initial angle between line ON and x -axis is =60^ Question: The magnitude of electric flux through area enclosed in square frame LMNO is -

Step-by-step solution

The direction of electric field is in x-y plane as shown in figure The magnitude of electric field is E= E_x^2+E_y^2 = 3+1 =2 V / m The direction of electric field is given by = ⁻¹ E_y E_x = ⁻¹ 1 3 =30^ Hence electric field is normal to square frame LMNO as shown in figure. electric flux = E A =E A 0=2 1=2 ~V / m C is correct option of Q. 15. Since flux is maximum at =60^ , rotation by 30^ either way would lead to decrease in flux. D is correct option of Q .16 . Lines ON and NM are both normal to uniform electric f