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Paragraph: In a young double slit experiment. The two slits are illuminated by a monochromatic light source S of wavelength =500 ~nm . Distance between slits and screen is D =2 ~m and distance between two slits S ₁ ~S ₂=10 m ₁=20 m and ₂= m , as shown in the figure. Answer the following questions on the basis above data. Question: What should be minimum thickness of a slab of refractive index =1.5 will be placed on t

Options

  1. A80
  2. B60
  3. C40
  4. D20

Correct answer

C. 40

Step-by-step solution

At C, phase difference = 2 ( ₂- ₁ )=80 Hence for maximum intensity will appear at C . Now for minimum intensity at C aligned & ( -1) t = 2 & t = t 2( -1) =500 ~nm aligned

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