Most Important Selected Qs for JEE AdvancedChemistryGeneral Principles and Processes of Isolation of Metals
A black mineral on roasting breaks up into two compounds (X) and (Y) with the liberation of a gas (Z) . When air is passed through the molten mixture of ( X ) and ( Y ) , both of them are converted into their respective oxides. One of them reduces its own oxide on further heating. Identify the mineral.
Options
- APyrogyrite
- BWillemite
- CChalcopyrites
- DChalcocite
Correct answer
C. Chalcopyrites
Step-by-step solution
The given black mineral is chalcopyrites which breaks up into Cu ₂ ~S . FeS and SO ₂ on roasting. aligned & 2 CuFeS ₂+ O ₂ ( Xi ₁ . Cu ₂ ~S + ( Y ) 2 FeS ₁ + (7) SO & 2 Cu ₂+3 O ₂ 2 Cu ₂ O +2 SO ₂ & 2 FeS ₂+3 O ₂ 2 FeO ₂+2 SO ₂ & Cu ₂ ~S +2 Cu ₂ O 6 Cu + SO ₂ aligned