There are two radio active substances A and B whose disintegration constants are λ_A and λ_B respectively. At t=0 the number of radioactive nuclei of A is N_ A 0 and that of B is N_ B 0 . It is known that λ_A λ_B and N_

Correct answer: C. R B will decay at slower rate than A . Also N_B N_A hence, R graph will indicate variation of In N_B with t .

JEE Advanced

JEE Advanced · Physics · Electromagnetic Waves

There are two radio active substances A and B whose disintegration...

There are two radio active substances

A

and

B

whose disintegration constants are

\lambda_A

and

\lambda_B

respectively. At

t=0

the number of radioactive nuclei of

A

N_{A 0}

and that of

B

N_{B 0}

. It is known that

\lambda_A\gt\lambda_B

and

N_{A 0} \lt N_{B 0}

. The broken line shows the variation of

\ln \left(N_A\right)

with respect to time for substance

A

. The graph of variation of

\operatorname{In}\left(N_B\right)

with respect to time

t

will be

C. $R$

B

will decay at slower rate than

A

. Also

N_B \gt N_A

hence,

R

graph will indicate variation of

\operatorname{In} N_B

with

t