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JEE Main 202628 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
28 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Redox Reactions

JEE Main 2026 · 28 January · Morning Shift · Chemistry · Redox Reactions

500 mL of 1.2 M KI solution is mixed with 500 mL of 0.2 M KMnO_ 4...

500 mL of 1.2 M KI solution is mixed with 500 mL of 0.2MKMnO40.2 \mathrm{M} \mathrm{KMnO}_{4} solution in basic medium. The liberated iodine was titrated with standard 0.1MNa2 S2O30.1 \mathrm{M} \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3} solution in the presence of starch indicator till the blue color disappeared. The volume (in L)ofNa2 S2O3of \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3} consumed is ____\_\_\_\_. (Nearest integer)

Correct answer

0

Step-by-step solution

MnO4−+I−→MnO2+I2MnO_4^- + I^- \rightarrow MnO_2 + I_2
I2+S2O32−→S4O62−+I−I_2 + S_2O_3^{2-} \rightarrow S_4O_6^{2-} + I^-
gram eq of KMnO4KMnO_4 = gram eq of Na2S2O3Na_2S_2O_3
0.2×5001000×3=0.1×V×10.2 \times \dfrac{500}{1000} \times 3 = 0.1 \times V \times 1
V=3 LV = 3 \text{ L}
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