500 mL of 1.2 M KI solution is mixed with 500 mL of 0.2 M KMnO ₄ solution in basic medium. The liberated iodine was titrated with standard 0.1 M Na ₂ ~S ₂ O ₃ solution in the presence of starch indicator till the blue color disappeared. The

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500 mL of 1.2 M KI solution is mixed with 500 mL of 0.2 M KMnO ₄ solution in basic medium. The liberated iodine was titrated with standard 0.1 M Na ₂ ~S ₂ O ₃ solution in the presence of starch indicator till the blue color disappeared. The volume (in L) of Na ₂ ~S ₂ O ₃ consumed is _ _ _ _ . (Nearest integer)

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Correct answer: 0

MnO₄^- + I^- MnO₂ + I₂ I₂ + S₂O₃²⁻ S₄O₆²⁻ + I^- gram eq of KMnO₄ = gram eq of Na₂S₂O₃ 0.2 500 1000 3 = 0.1 V 1 V = 3 L

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