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In a standard meter bridge experiment, to measure the specific resistance of a wire the following data are found:- Length ( L )=(1 .01) m measured by a meter scale Radius of wire =1 ~mm .01 ~mm . (measured by screw gauge). Resistance of wire (R)=(5 .01) The maximum possible error in the measurement of specific resistance is (You may use the formula:- = r^2 ~L R )

Options

  1. A1 m
  2. B2 m
  3. C5024 m
  4. D6024 m

Correct answer

C. 5024 m

Step-by-step solution

= 3 14 10⁻⁶ 5 1 =15.7 ohm metre = [ 2 r r + L L + R R ] ohm metre. =15 7 [2 .01 1 + .01 1 + .01 5 ] ohm metre aligned & =15.7 [ 02+ 01+ 002] ohm - metre & =15.7 032 m & =.5024 m aligned

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