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JEE Advanced
Exam
JEE Advanced
Subject
Physics
Chapter
Mathematics in Physics

JEE Advanced · Physics · Mathematics in Physics

When a piece of wire is held diametrically in a screw gauge [pitch...

When a piece of wire is held diametrically in a screw gauge [pitch =1 mm=1 \mathrm{~mm}, number of division on circular scale =100]=100]. The readings obtained are as shown: When a piece of wire is held diametrically in a screw gauge [pitch =1 ~mm , number of division on circular scale =100]
When a piece of wire is held diametrically in a screw gauge [pitch =1 ~mm , number of division on circular scale =100]
Now if we measure the same with help of vernier callipers [ 1MSD=1 mm,101 \mathrm{MSD}=1 \mathrm{~mm}, 10 divisions of vernier coinciding with 9 divisions of main scale] having a negative zero error of 0.5 mm , then find which of the following figures correctly represents the reading.

Options

  1. AA ball is thrown at an angle of 60^ above the horizontal. If its speed at the maximum height is 15 m s^ -1 , what is
  2. BA ball is thrown at an angle of 60^ above the horizontal. If its speed at the maximum height is 15 m s^ -1 , what is
  3. CA ball is thrown at an angle of 60^ above the horizontal. If its speed at the maximum height is 15 m s^ -1 , what is
  4. DA ball is thrown at an angle of 60^ above the horizontal. If its speed at the maximum height is 15 m s^ -1 , what is

Correct answer

A. A ball is thrown at an angle of 60^ above the horizontal. If its speed at the maximum height is 15 m s^ -1 , what is

Step-by-step solution

From screw gauge z.e. =+0.20 mm=+0.20 \mathrm{~mm} Dia of chalk =3.5−0.2=3.3 mm=0.33 cm=3.5-0.2=3.3 \mathrm{~mm}=0.33 \mathrm{~cm} For vernier callipers, z.e. =−0.05 cm=-0.05 \mathrm{~cm} Thus it must show 0.33−0.05=0.28 cm0.33-0.05=0.28 \mathrm{~cm} so (a) is correct
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