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JEE Advanced
Exam
JEE Advanced
Subject
Physics
Chapter
Mechanical Properties of Solids

JEE Advanced · Physics · Mechanical Properties of Solids

A uniform rod is kept at smooth horizontal surface, a constant...

A uniform rod is kept at smooth horizontal surface, a constant force is applied on the rod in horizontal direction at end ' AA '. Find the ratio of energy stored per unit volume at end AA to the energy stored per unit volume in the middle of rod. A uniform rod is kept at smooth horizontal surface, a constant force is applied on the rod in horizontal direction at

Options

  1. A22
  2. B44
  3. C88
  4. D66

Correct answer

B. 44

Step-by-step solution

u=12( stress )2Yu=\frac{1}{2} \frac{(\text { stress })^2}{Y}  Stress = Tension  area \text { Stress }=\frac{\text { Tension }}{\text { area }} UAUmiddle =TA2( Tmiddle )2=F2( F/2)2=4\frac{\mathrm{U}_{\mathrm{A}}}{\mathrm{U}_{\text {middle }}}=\frac{\mathrm{T}_{\mathrm{A}}^2}{\left(\mathrm{~T}_{\text {middle }}\right)^2}=\frac{\mathrm{F}^2}{(\mathrm{~F} / 2)^2}=4
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