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Most Important Selected Qs for JEE AdvancedPhysicsMotion in One Dimension

A particle is placed in a cart. Initial location of the particle is taken as origin in ground frame. At t=0 , the cart starts moving along x -axis with uniform velocity 2 ~m / s and at the same instant the particle starts moving with 2 x j relative to cart where x is x -coordinate of the cart. Which of the following is the radius of curvature of the trajectory of the particle in ground frame when it's tangential acce

Options

  1. A1 2 m
  2. B2 2 ~m
  3. C3 2 2 ~m
  4. D4 2 m

Correct answer

D. 4 2 m

Step-by-step solution

V _ P G = V _ P C + V _ C G =2 x j +2 i Hence, for the paritcle, V _ x =2 ~m / s and V _ y =2 x =4 t a _ x =0 a _ y =4 ~m / s ^2 x =2 t , y =2 t ^2 a_ Total =4 ~m / s ^2 (a) (along Y-axis) and trajectory y=2 x^2 4 = x^2 2 when | a _ |= | a _N |, a =a =45^ So, V_x=V_y=2 V=2 2 R_C= V ^2 a _ N = 4 2 4 45^ =2 2 ~m = 4 2 ~m

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