Most Important Selected Qs for JEE AdvancedPhysicsWave Optics
At a point on the screen in YDSE experiment 3rd maxima is observed at t=0 . Now screen is slowly moved with constant speed away from the slits in such a way that the centre of slits and centre of screen lie on the same, line always and at t=1 sec the intensity at that point is observed (3/4)th of maximum intensity in between 2nd and 3rd maxima. The speed of screen may be ( D= separation between the screen and slits d
Options
- A7 D 13
- B13 D 5
- CD 17
- DNone of these
Correct answer
C. D 17
Step-by-step solution
O P= 3 D d Corresponding path difference at position mentioned is (2+1 / 6) or (3-1 / 6) aligned & 13 6 (D+v) d = 3 D d v= 5 D 13 & or 17 6 d (D+v)= 3 D d v= D 17 aligned