Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
Most Important Selected Qs for JEE AdvancedMathematicsContinuity and Differentiability

Paragraph: Match the condition of column-I with corresponding number of real roots of f(x)=0 is column-II and number of points of non-derivability of y=f(|x|) in column-III, where f(x)=a x^2+b x+c . ( array l|l|l Column-I & Column-II & Column-III (I) a^2+b^2+c^2-a b-b c-c a 0 & (i) 0 & (P) 0 (II) a^2+b^2+c^2+a b+b c+c a 0 & (ii) 1 & (Q) 1 (III) 3 (a^2+b^2+c^2+1 ) 2(a+b+c+a b+b c+c a) & (iii) 2 & (R) 3 (IV) a^2+b^2+c^

Options

  1. A(I) (i) (P)
  2. B(I) (iii) (Q)
  3. C(II) (iv) (P)
  4. D(II) (ii) (Q)

Correct answer

C. (II) (iv) (P)

Step-by-step solution

I) array ll & a^2+b^2+c^2-a b-b c-c a 0 & (a-b)^2+(b-c)^2+(c-a)^2 0 a=b=c & f(x)=a x^2+a x+a & D < 0 & no real root & |f(|x|)| is always derivable except one point. & (I) (i) (Q) array (II) array ll & a^2+b^2+c^2+a b+b c+c a 0 (a+b)^2+(b+c)^2+(c+a)^2 0 & a+b=0, b+c=0, c+a=0 & a=b=c=0 & f(x)=a x^2+b x+c is an identify & f(x)=0 has infinite roots & f(x) is always derivable. & (II) (iv) (P) array (III) aligned & (a-1)^2+(b-1)^2+(c-1)^2+(a-b)^2+(b-c)^2+(c-a)^2 0 & a=b=c=1 aligned f(x)=0 has no real root and |f(|x|)| is

Practice Continuity and Differentiability on Quantrex Academy →

More from Continuity and Differentiability

Let R denote the set of all real numbers. Let f : R R be an arbitrary function and let g : R R be the function defined by g(x) = x f(x) , for all x R . Then which of the following 2026Consider the function f : (- 2 , 2 ) (- , ) defined by f(x) = (|x| + |x - 1|) x + [x x] , where [x x] is the greatest integer less than or equal to x x . Let be the total number of 2026For a real number , let [ ] denote the greatest integer less than or equal to . For a finite set S , let |S| denote the number of elements in the set S . Consider the functions f : 2026For the function f(x) = e^ |x| - |x| , x R , consider the following statements: Statement I: f is differentiable for all x R . Statement II: f is increasing in (- , - 2 ) . In the 2026Let f(x) = cases 1 3 , & x /2 b(1- x) ( -2x)^2 , & x > /2 cases . If f is continuous at x= /2 , then the value of ₀^ 3b-6 |x^2+2x-3| ,dx is: 2026Let f(x) = cases x^3 + 8 ; & x Then the number of points, where the function g f is discontinuous, is __________. 2026Let f(x)= cases e^ x-1 , & x<0 x^2-5x+6, & x 0 cases and g(x)=f(|x|)+|f(x)| . If the number of points where g is not continuous and is not differentiable are and respectively, then 2026The number of points, at which the function f(x) = 6x, 2 + 3x^2 + |x - 1| | |x^2 - 1 4 | | , x (- , ) , is not differentiable, is _____. 2026 Full Continuity and Differentiability list All Most Important Selected Qs for JEE Advanced PYQs