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Most Important Selected Qs for JEE AdvancedMathematicsContinuity and Differentiability

If f(x+y)=f(x)+f(y)+|x| y+x y^2, x, y R and f^ (0)=0 then

Options

  1. Af(x) is twice differentiable at x=0
  2. Barea bounded by f(x), x=1, y=0 is 1 3
  3. Cf^ (x) is continuous x R
  4. Df^ (x) is differentiable x R

Correct answer

C. f^ (x) is continuous x R

Step-by-step solution

f(x)= x|x| 2

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