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Consider a sequence f(x), n I⁺ 0 defined by f(0)=0, f(n+1)= 6+f(n) then _ n f(n) is

Options

  1. A1
  2. B2
  3. C3
  4. Dnone of these

Correct answer

C. 3

Step-by-step solution

f(0) f(1) now if suppose f(n-1) f(n) f(n-1)+6 f(n)+6 f(n) f(n+1) Also, f(0) 3 , let f(n) 3 f(n)+6 3+6 f(n+1) 3 So, f(n) is bounded above 3

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