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Olympiad workbook
Exam
Olympiad workbook
Subject
IOQM
Chapter
Properties of Triangles

Olympiad workbook · IOQM · Properties of Triangles

Let A B C be an acute-angled triangle and P be a point in its...

Let ABCA B C be an acute-angled triangle and P be a point in its interior. Let PA,PBP_A, P_B, and PCP_C be the images of PP under reflection in the sides BC,CAB C, C A and ABA B, respectively. If PP is the orthocentre of the triangle PAPBPCP_A P_B P_C and if the largest angle of the triangle that can be formed by the line segments PAP A, PBP B, and PCP C is x∘x^{\circ}; determine the value of xx.Let A B C be an acute-angled triangle and P be a point in its interior. Let P_A, P_B , and P_C be the images of P under

Correct answer

60

Step-by-step solution

Let A B C be an acute-angled triangle and P be a point in its interior. Let P_A, P_B , and P_C be the images of P under
ABA B is ⊥\perp bisector PPC&ACP P_C \& A C is ⊥\perp bisector of PPBP P_B. AA is point of intersection of ⊥\perp bisectors AA is circumcentre of △PPBPC\triangle P P_B P_C  Circumradius =CR(ΔPPBPC)=PA\text { Circumradius }=C R\left(\Delta P P_B P_C\right)=P A Similarly, CR(ΔPPCPA)=PBC R\left(\Delta P P_C P_A\right)=P B &CR(ΔPPAPB)=PC\& C R\left(\Delta P P_A P_B\right)=P C But CR(ΔPPAPB)=CR(ΔPPBPC)=CR(ΔPPCPA)=CR(ΔPAPBPC)C R\left(\Delta P P_A P_B\right)=C R\left(\Delta P P_B P_C\right)=C R\left(\Delta P P_C P_A\right)= C R\left(\Delta P_A P_B P_C\right)P C=P A=P B=C R\left(\Delta P_A P_B P_C\right)PA=PC⇒P A=P C \Rightarrow Required triangle is equilateral triangle ⇒x=60∘\Rightarrow x=60^{\circ}
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