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Olympiad workbook
Exam
Olympiad workbook
Subject
IOQM
Chapter
Properties of Triangles

Olympiad workbook · IOQM · Properties of Triangles

In a triangle ABC , right-angled at A , the altitude through A and...

In a triangle ABC , right-angled at A , the altitude through A and the internal bisector of ∠A\angle \mathrm{A} have lengths 3 and 4, respectively. Find the length of the median through A .In a triangle ABC , right-angled at A , the altitude through A and the internal bisector of A have lengths 3 and 4,

Correct answer

24

Step-by-step solution

In a triangle ABC , right-angled at A , the altitude through A and the internal bisector of A have lengths 3 and 4,
∠CAE=45∘=∠BAEAD=3\begin{aligned} & \angle \mathrm{CAE}=45^{\circ}=\angle \mathrm{BAE} \\ & \mathrm{AD}=3\end{aligned} Let BC=a,CA=b,AB=cB C=a, C A=b, A B=c 12bc=12⋅a⋅3⇒bc=3a2bcb+ccos⁡A2=4⇒6ab+c⋅12=4⇒22(b+c)=3a⇒8(b2+c2+2bc)=9a2⇒8(a2+6a)=9a2⇒48a=a2⇒a=48\begin{aligned} & \frac{1}{2} b c=\frac{1}{2} \cdot a \cdot 3 \Rightarrow b c=3 a \\ & \frac{2 b c}{b+c} \cos \frac{A}{2}=4 \Rightarrow \frac{6 a}{b+c} \cdot \frac{1}{\sqrt{2}}=4 \\ & \Rightarrow 2 \sqrt{2}(b+c)=3 a \\ & \Rightarrow 8\left(b^2+c^2+2 b c\right)=9 a^2 \\ & \Rightarrow 8\left(a^2+6 a\right)=9 a^2 \\ & \Rightarrow 48 a=a^2 \Rightarrow a=48 \end{aligned} So AF=a2=24\mathrm{AF}=\frac{\mathrm{a}}{2}=24
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