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Olympiad workbook
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Olympiad workbook
Subject
IOQM
Chapter
Quadratic Equation

Olympiad workbook · IOQM · Quadratic Equation

Let a, b be positive integers satisfying a^3-b^3-a b=25 . Find the...

Let a,ba, b be positive integers satisfying a3−b3−ab=25a^3-b^3-a b=25. Find the largest possible value of a2+b3a^2+b^3.

Correct answer

43

Step-by-step solution

a3−b3−ab=25a^3-b^3-a b=25 for a=4a=4 and b=3b=3 Because for any greater number a3−b3−ab>25a^3-b^3-a b>25 To prove this if a>ba>b, then a3−b3−aba^3-b^3-a b =(b+t)3−b3−b(b+t),t>0=(3t−1)b2+(3t2−t)b+t3 is always greater than 4\begin{aligned} & =(b+t)^3-b^3-b(b+t), t>0 \\ & =(3 t-1) b^2+\left(3 t^2-t\right) b+t^3 \text { is always greater than } 4 \end{aligned} then b≥3b \geq 3 So, a2+b3=42+33=43a^2+b^3=4^2+3^3=43
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