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Olympiad workbook
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Olympiad workbook
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IOQM
Chapter
Quadratic Equation

Olympiad workbook · IOQM · Quadratic Equation

Let a, b be integers such that all the roots of the equation (x^2+a...

Let a,ba, b be integers such that all the roots of the equation \left(x^2+a x+20\right)(x2+17x+b)=0\left(x^2+17 x+b\right)=0 are negative integers. What is the smallest possible value of a+b\mathrm{a}+\mathrm{b} ?Let a, b be integers such that all the roots of the equation (x^2+a x+20) (x^2+17 x+b)=0 are negative integers. What is

Correct answer

25

Step-by-step solution

Let a, b be integers such that all the roots of the equation (x^2+a x+20) (x^2+17 x+b)=0 are negative integers. What is
 so a>0 and b>0 since sum of roots <0 and product >0( since 20=(1×20)×(2×10) or (4×5)min⁡a=9−17=α+β⇒(αβ)≡(−1,−16),(−2,−15),(−8,−9)min⁡b=16(a+b)min⁡=amin⁡+bmin⁡=9+16=25\begin{aligned} & \text { so } a>0 \text { and } b>0 \text { since sum of roots } < 0 \text { and product }>0 \\ & (\text { since } 20=(1 \times 20) \times(2 \times 10) \text { or }(4 \times 5) \\ & \min a=9 \\ & -17=\alpha+\beta \Rightarrow(\alpha \beta) \equiv(-1,-16),(-2,-15),(-8,-9) \\ & \min b=16 \\ & (a+b)_{\min }=a_{\min }+b_{\min }=9+16=25\end{aligned}
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