Consider a square A B C D of side length 16 . Let E, F be points on...
Consider a square ABCD of side length 16 . Let E,F be points on CD such that CE=EF=FD. Let the line BF and AE meet in M. The area of △MAB is:
Correct answer
96
Step-by-step solution
Eq of line AE:2y−3x+16=0
Eq of line BF : 2y+3x−32=0⇒M≡(8,4)
Area of triangle AMB21016816164111∣∣=21(−16(8)+1(64−8×16))=21(−16×16+64)=216(4−16)=8×12=96 sq.units