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Olympiad workbook
Exam
Olympiad workbook
Subject
IOQM
Chapter
Straight Lines

Olympiad workbook · IOQM · Straight Lines

In a rectangle A B C D, E is the midpoint of A B: F is point on A C...

In a rectangle ABCD,EA B C D, E is the midpoint of AB:FA B: F is point on ACA C such that BFB F is perpendicular to ACA C and FEF E perpendicular to BDB D. Suppose BC=83B C=8 \sqrt{3}. Find ABA B.In a rectangle A B C D, E is the midpoint of A B: F is point on A C such that B F is perpendicular to A C and F E

Correct answer

24

Step-by-step solution

sin⁡θ=832x=43x\sin \theta=\frac{8 \sqrt{3}}{2 x}=\frac{4 \sqrt{3}}{x} In a rectangle A B C D, E is the midpoint of A B: F is point on A C such that B F is perpendicular to A C and F E
FA=2xcos⁡θFB=2xsin⁡θMB=FBxsin⁡2θ=2xsin⁡θsin⁡2θME2+MB2=BE2=x2x2sin⁡2θ+4x2sin⁡2θsin⁡22θ=x2sin⁡2θ+4sin⁡2θsin⁡22θ=14sin⁡2θsin⁡22θ=cos⁡2θ16sin⁡4θ=1sin⁡2θ=14⇒sin⁡θ=1243x=13⇒x=12⇒2x=AB=24 Ans. \begin{aligned} & F A=2 x \cos \theta \\ & F B=2 x \sin \theta \\ & M B=F B x \sin 2 \theta=2 x \sin \theta \sin 2 \theta \\ & M E^2+M B^2=B E^2=x^2 \\ & x^2 \sin ^2 \theta+4 x^2 \sin ^2 \theta \sin ^2 2 \theta=x^2 \\ & \sin ^2 \theta+4 \sin ^2 \theta \sin ^2 2 \theta=1 \\ & 4 \sin ^2 \theta \sin ^2 2 \theta=\cos ^2 \theta \\ & 16 \sin ^4 \theta=1 \\ & \sin ^2 \theta=\frac{1}{4} \quad \Rightarrow \quad \sin \theta=\frac{1}{2} \\ & \frac{4 \sqrt{3}}{x}=\frac{1}{\sqrt{3}} \quad \Rightarrow \quad x=12 \Rightarrow 2 x=A B=24 \text { Ans. } \end{aligned}
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