Compound P on treatment with CH_2 ~N_2 (diazomethane) produces...

Compound P on treatment with

\mathrm{CH}_2 \mathrm{~N}_2

(diazomethane) produces compound Q . Compound Q on reaction with HI produces two alkyl iodides R and S . Alkyl iodide S with higher number of carbon atoms on reaction with KCN followed by hydrolysis gives 3 -methylbutanoic acid. The compound P is

Options

A2-butanol
B1-butanol
C2-methyl-2-propanol
D2-methyl-1-propanol

Correct answer

D. 2-methyl-1-propanol

Step-by-step solution

No Solution

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