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Olympiad workbook

Exam: Olympiad workbook
Subject: NSEC
Chapter: Chemical Bonding and Molecular Structure

Olympiad workbook · NSEC · Chemical Bonding and Molecular Structure

In ammonia the bond angle is 107^ ^ ^ 48^ while in SbH_3 the bond...

In ammonia the bond angle is

107^{{}^{{}^{\circ}}} 48^{\prime}

while in

\mathrm{SbH}_3

the bond angle is about

91^{{}^{{}^{\circ}}} 18^{\prime}

. The correct explanation among the followings is/ are

Options

AThe orbitals of Sb used for the formation of $\mathrm{Sb}-\mathrm{H}$ bond are almost pure p-orbitals.
BSb has larger size compared to N .
CSb has more metallic character than N .
DAll the statements are correct.

Correct answer

A. The orbitals of Sb used for the formation of $\mathrm{Sb}-\mathrm{H}$ bond are almost pure p-orbitals.

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