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A half-cell reaction represented by (i) as given below Fe ( OH )₂( ~s )+2 e⁻ Fe ( ~s )+2 OH ⁻( aq ) E^ =-0.9 ~V (i) takes place in two different electrochemical cells, I and II, in which the other half cell reactions are (ii) and (iii) respectively: array ll A l³⁺(a q)+3 e⁻ A l(s) & E^ =-1.7 ~V (ii) A g B r(s)+e⁻ A g(s)+B r⁻(a q) & E^ =-0.07 ~V (iii) array The correct option that represents the redox reactions in cel

Options

  1. AFe is oxidised in cell I; Fe is oxidised in cell II
  2. BFe is oxidised in cell I; Fe is reduced in cell II
  3. CFe is reduced in cell I ; Fe is reduced in cell II
  4. DFe is reduced in cell I; Fe is oxidised in cell II

Correct answer

D. Fe is reduced in cell I; Fe is oxidised in cell II

Step-by-step solution

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