Ellingham diagrams are plots of Δ G^0 vs temperature which have...

Ellingham diagrams are plots of $\Delta \mathrm{G}^0$ vs temperature which have applications in metallurgy. $2 \mathrm{H}_2+\mathrm{O}_2=2 \mathrm{H}_2 \mathrm{O} \quad \Delta \mathrm{G}(\mathrm{~J})=-247500+55.85 \mathrm{~T} \ldots \ldots (I)2 \mathrm{CO}+\mathrm{O}_2=2 \mathrm{CO}_2 \quad \Delta \mathrm{G}(\mathrm{~J})=-282400+86.81 \mathrm{~T} \ldots \ldots (II)$ The Ellingham diagrams for the oxidation of $\mathrm{H}_2$ (I) and CO (II) are given below. The two lines intersect $\left(\mathrm{T}_{\mathrm{E}}\right)$ at 1125 K .
Which of the following is correct? I. $\Delta \mathrm{G}^{{}^{{}^{\circ}}}$ for reaction (i) is more negative at $\mathrm{T} < 1125 \mathrm{~K}$ II. $\Delta \mathrm{G}^{{}^{{}^{\circ}}}$ for the reduction of CO is more negative at $\mathrm{T} < 1125 \mathrm{~K}$ III. $\mathrm{H}_2$ is a better reducing agent at $\mathrm{T}>1125 \mathrm{~K}$ IV. $\mathrm{H}_2$ is a better reducing agent at $\mathrm{T} < 1125 \mathrm{~K}$