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Olympiad workbook
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NSEP
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Atomic Physics

Olympiad workbook · NSEP · Atomic Physics

A hydrogen atom is in ground state ( n=1 ). The magnetic field...

A hydrogen atom is in ground state ( n=1\mathrm{n}=1 ). The magnetic field produced by revolving electron, at centre of atom is B0\mathrm{B}_0. Atom is excited to state n=4\mathrm{n}=4. According to Bohr model, the correct alternative(s) is/are

Options

  1. AMagnetic field at centre of atom for (n=4)(n=4) becomes B4=B064B_4=\frac{B_0}{64}
  2. BEnergy absorbed by atom in going from (n=1)(n=1) to (n=4)(n=4) is 12.75 eV
  3. CChange in magnitude of angular momentum of electron is 3h2π\frac{3 h}{2 \pi}
  4. DAssume that this excited atom (n=4)(n=4) is at rest and it makes transition to ground state (n=1)(n=1) in a single quantum jump of an electron, (Take mass of atom MH=1.67×10−27Kg\mathrm{M}_{\mathrm{H}}=1.67 \times 10^{-27} \mathrm{Kg} ) the recoil speed of atom will be nearly v=4.1 ms−1\mathrm{v}=4.1 \mathrm{~ms}^{-1}.

Correct answer

D. Assume that this excited atom (n=4)(n=4) is at rest and it makes transition to ground state (n=1)(n=1) in a single quantum jump of an electron, (Take mass of atom MH=1.67×10−27Kg\mathrm{M}_{\mathrm{H}}=1.67 \times 10^{-27} \mathrm{Kg} ) the recoil speed of atom will be nearly v=4.1 ms−1\mathrm{v}=4.1 \mathrm{~ms}^{-1}.

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