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The distance between two slits in Young's double slits experiment is d =2.5 ~mm and the distance of the screen from the plane of slits is D=120 ~cm . The slits are illuminated with coherent beam of light of wavelength =600 ~nm . The minimum distance (from the central maximum) of a point where the intensity reduces to 25 % of maximum intensity is

Options

  1. A24 ~m
  2. B48 ~m
  3. C96 ~m
  4. D120 ~m

Correct answer

C. 96 ~m

Step-by-step solution

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