Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
Olympiad workbookNSEPWave Optics

In a young's double slit experiment distance between slits is d =1 ~mm , Wavelength of light used is 600 nm and distance of screen from the plane of slits is D =1 ~m . The minimum distance between two points on the screen where intensity falls to 75 % of maximum intensity will be (Assume both sources of equal power).

Options

  1. A0.1 mm
  2. B0.2 mm
  3. C0.45 mm
  4. D0.9 mm

Correct answer

B. 0.2 mm

Step-by-step solution

No Solution

Practice Wave Optics on Quantrex Academy →

More from Wave Optics

A slit of width a is illuminated by parallel monochromatic light of wavelength . The value of a at which the first minimum of the diffraction pattern will form at =30^ isInitially interference is observed with the entire experimental set up inside a chamber filled with air. Now the chamber is evacuated. With the same source of light used, a carefulThe Hubble telescope in orbit above the earth has a 2.4 m circular aperture. The telescope has equipment for detecting ultraviolet light. The minimum angular separation between twoConsider the diffraction pattern due to a single slit. The first maximum for a certain monochromatic light coincides with the first minimum for red light of wavelength 660 nm . TheWhich of the following sources emits light having highest degree of coherence?Light of wavelength 640 nm falls on a plane diffraction grating with 12000 lines per inch. In the diffraction pattern on a screen kept at a distance of 12 cm from the grating, the An unpolarized light of intensity 32 ~W / m ^2 passes through three polarizers, such that the transmission axis of last polarizer is crossed with that of the first. If the intensitWhite light is used to illuminate two slits in Young's double sit experiment. Separation between the two slits is b and the screen is at a distance D( b) from the plane of slits. T Full Wave Optics list All Olympiad workbook PYQs