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An electrochemical cell was constructed with Fe ²⁺ / Fe and Cd ²⁺ / Cd at 25^ C with initial concentrations of [ Fe ²⁺ ]=0.800 M and [ Cd ²⁺ ]=0.250 M . The EMF of the cell when [ Cd ²⁺ ] becomes 0.100 M is Half cell E^0(V) Fe ²⁺( aq ) / Fe ( s ) -0.44 Cd ²⁺( aq ) / Cd ( s ) -0.40

Options

  1. A0.013 V
  2. B0.011 V
  3. C0.051 V
  4. D0.022 V

Correct answer

B. 0.011 V

Step-by-step solution

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