Olympiad workbook
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- Olympiad workbook
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- NSEC
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- Electrochemistry
Olympiad workbook · NSEC · Electrochemistry
The correct order of the following oxidizing agents in basic...
The correct order of the following oxidizing agents in basic aqueous medium is:
\begin{array}{ll}
\mathrm{CrO}}_{4}{ }^{2-}/ \mathrm{Cr}^{3+}& \mathrm{E}^0=-0.11 \mathrm{~V}\\
\mathrm{FeO}}_{4}{ }^{2-}/ \mathrm{Fe}^{3+} \text{ and } \mathrm{E}^0=+0.72 \mathrm{~V}\\
\mathrm{MnO}}_{4}{ }^{2-}/ \mathrm{Mn}^{3+}& \mathrm{E}^0=+0.46 \mathrm{~V}
\end{array}
Options
- A\left[\mathrm{CrO}_4\right]^{2-}>\left[\mathrm{FeO}_4\right]^{2-}>\left[\mathrm{MnO}_4\right]^{2-}
- B\left[\mathrm{FeO}_4\right]^{2-}>\left[\mathrm{MnO}_4\right]^{2-}>\left[\mathrm{CrO}_4\right]^{2-}
- C\left[\mathrm{CrO}_4\right]^{2-}>\left[\mathrm{MnO}_4\right]^{2-}>\left[\mathrm{FeO}_4\right]^{2-}
- D\left[\mathrm{MnO}_4\right]^{2-}>\left[\mathrm{FeO}_4\right]^{2-}>\left[\mathrm{CrO}_4\right]^{2-}
Correct answer
B. \left[\mathrm{FeO}_4\right]^{2-}>\left[\mathrm{MnO}_4\right]^{2-}>\left[\mathrm{CrO}_4\right]^{2-}
Step-by-step solution
No Solution