Reaction of BeO with ammonia and hydrogen fluoride gives ' A '...

Reaction of $BeO$ with ammonia and hydrogen fluoride gives $' A '$ which on thermal decomposition gives ${BeF}_{2}$ and ${NH}_{4}F$ . What is $' A '$ ?

Options

A ${H}_{3}{NBeF}_{3}$
B
${\left({NH}_{4}\right)}_{2}{BeF}_{4}$
C
$\left({NH}_{4}\right)\left({BeF}_{3}\right)$
D
${\left({NH}_{4}\right)}_{2}\left({Be}_{2}{F}_{6}\right)$

Correct answer

${\left({NH}_{4}\right)}_{2}{BeF}_{4}$

Step-by-step solution

Beryllium ion forms tetra coordinated complexes readily due to the presence of $2sand2p$ empty subshells as shown below.

Reaction of BeO with ammonia and hydrogen fluoride gives ' A ' which on thermal decomposition gives BeF _ 2 and NH _ 4

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