When a certain metal was irradiated with light of frequency 3.2 ×...

When a certain metal was irradiated with light of frequency

3.2 \times 10^{16} \mathrm{~Hz}

, the photoelectrons emitted had twice the kinetic energy as did the photoelectrons emitted when the same metal was irradiated with light of frequency

2.0 \times 10^{16} \mathrm{~Hz}

. The

v_0

of the metal is

Options

A $2.4 \times 10^{16} \mathrm{~Hz}$
B $8.0 \times 10^{16} \mathrm{~Hz}$
C $8.0 \times 10^{15} \mathrm{~Hz}$
D $7.2 \times 10^{16} \mathrm{~Hz}$

Correct answer

C. $8.0 \times 10^{15} \mathrm{~Hz}$

Step-by-step solution

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