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Olympiad workbook
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NSEC
Chapter
Thermodynamics (C)

Olympiad workbook · NSEC · Thermodynamics (C)

Hydrazine used in rocket fuels can be obtained by the reaction of...

Hydrazine used in rocket fuels can be obtained by the reaction of ammonia and hydrogen peroxide according to the following equation 2NH3( g)+H2O2(l)→N2H4(l)+2H2O(l)2 \mathrm{NH}_3(\mathrm{~g})+\mathrm{H}_2 \mathrm{O}_2(\mathrm{l}) \rightarrow \mathrm{N}_2 \mathrm{H}_4(\mathrm{l})+2 \mathrm{H}_2 \mathrm{O}(\mathrm{l})\left(\Delta \mathrm{H}^0\right.reaction=−241 kJ/mol)reaction \left.=-241 \mathrm{~kJ} / \mathrm{mol}\right) If ΔH0\Delta \mathrm{H}^0 (formation)ofNH3,H2O2of \mathrm{NH}_3, \mathrm{H}_2 \mathrm{O}_2 and H2O\mathrm{H}_2 \mathrm{O} are −46.1,−187.8-46.1,-187.8 and −285.8 kJ/mol-285.8 \mathrm{~kJ} / \mathrm{mol} respectively, ΔH0\Delta \mathrm{H}^0 for the decomposition of hydrazine into N2\mathrm{N}_2 and H2\mathrm{H}_2 is

Options

  1. A50.6 kJ/mol50.6 \mathrm{~kJ} / \mathrm{mol}
  2. B241 kJ/mol241 \mathrm{~kJ} / \mathrm{mol}
  3. C−50.6 kJ/mol-50.6 \mathrm{~kJ} / \mathrm{mol}
  4. D120.5 kJ/mol120.5 \mathrm{~kJ} / \mathrm{mol}

Correct answer

C. −50.6 kJ/mol-50.6 \mathrm{~kJ} / \mathrm{mol}

Step-by-step solution

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