JEE Main202227 Jun 2022Morning ShiftChemistrys Block ElementsActual
BeCl 2 reacts with LiAlH 4 to give
Options
- ABe + Li AlCl 4 + H 2
- BBe + AlH 3 + LiCl + HCl
- CBeH 2 + LiCl + AlCl 3
- DBeH 2 + Li AlCl 4
Correct answer
C. BeH 2 + LiCl + AlCl 3
Step-by-step solution
All the elements except beryllium combine with hydrogen upon heating to form their hydrides,   MH 2 . BeH 2 , however, can be prepared by the reaction of BeCl 2 with LiAlH 4 . . 2 BeCl 2 + LiAlH 4 → 2 BeH 2 + LiCl + AlCl 3