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JEE Main 202227 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
27 June
Shift
Morning Shift
Subject
Chemistry
Chapter
s Block Elements

JEE Main 2022 · 27 June · Morning Shift · Chemistry · s Block Elements

BeCl _ 2 reacts with LiAlH _ 4 to give

BeCl2{BeCl}_{2} reacts with LiAlH4{LiAlH}_{4} to give

Options

  1. ABe+Li[AlCl4]+H2Be + Li\left[{AlCl}_{4}\right] + {H}_{2}
  2. BBe+AlH3+LiCl+HClBe + {AlH}_{3} + LiCl + HCl
  3. CBeH2+LiCl+AlCl3{BeH}_{2} + LiCl + {AlCl}_{3}
  4. DBeH2+Li[AlCl4]{BeH}_{2} + Li\left[{AlCl}_{4}\right]

Correct answer

C. BeH2+LiCl+AlCl3{BeH}_{2} + LiCl + {AlCl}_{3}

Step-by-step solution

All the elements except beryllium combine with hydrogen upon heating to form their hydrides,MH2{MH}_{2}. BeH2{BeH}_{2}, however, can be prepared by the reaction of BeCl2{BeCl}_{2} with LiAlH4{LiAlH}_{4}. .

2BeCl2+LiAlH4→2BeH2+LiCl+AlCl32{BeCl}_{2} + {LiAlH}_{4} \to 2{BeH}_{2} + LiCl + {AlCl}_{3}

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