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Olympiad workbook
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IOQM
Chapter
Quadratic Equation

Olympiad workbook · IOQM · Quadratic Equation

Suppose an integer r , a natural number n and a prime number p...

Suppose an integer r , a natural number n and a prime number p satisfy the equation 7x2−44x+12=pn7 x^2-44 x+12=p^n. Find the largest value of pp.

Correct answer

47

Step-by-step solution

7x2−44x+12=pn7x2−42x−2x+12=pn(7x−2)(x−6)=pn7x−2=pα and x−6=pβ(7x−2)−7(x−6)=pα−7pβ40=pα−7pβ If α,β∈N,p is divisors of 40⇒p=2 or 5 If p=2,40=2α−7.2β⇒23.5=2α−7.2β⇒β=3 and 2α=40+56⇒α∉Z hence not possible  If p=5 then 40=5α−7.5β⇒23.5=5α−7.5β⇒β=1 and 5α=40+35⇒α∉Z hence not possible  so β=0⇒pα=47⇒p=47 and α=1\begin{array}{ll}7 x^2-44 x+12=p^n & \\ 7 x^2-42 x-2 x+12=p^n & \\ (7 x-2)(x-6)=p^n & \\ 7 x-2=p^\alpha \text { and } x-6=p^\beta & \\ (7 x-2)-7(x-6)=p^\alpha-7 p^\beta & \\ 40=p^\alpha-7 p^\beta & \\ \text { If } \alpha, \beta \in N, p \text { is divisors of } 40 & \Rightarrow p=2 \text { or } 5 \\ \text { If } p=2,40=2^\alpha-7.2^\beta & \Rightarrow 2^3 .5=2^\alpha-7.2^\beta \\ \Rightarrow \beta=3 \text { and } 2^\alpha=40+56 & \Rightarrow \alpha \notin Z \text { hence not possible } \\ \text { If } p=5 \text { then } 40=5^\alpha-7.5^\beta & \Rightarrow 2^3 .5=5^\alpha-7.5^\beta \\ \Rightarrow \beta=1 \text { and } 5^\alpha=40+35 & \Rightarrow \alpha \notin Z \text { hence not possible } \\ \text { so } \beta=0 \Rightarrow p^\alpha=47 & \Rightarrow p=47 \text { and } \alpha=1\end{array}
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