JEE Main20231 Feb 2023Evening ShiftChemistrySurface ChemistryActual
In figure, a straight line is given for Freundrich Adsorption ( y = 3 x + 2 . 505 ) . The value of 1 n and logK are respectively.
Options
- A0 . 3 and log   2 . 505
- B0 . 3 and 0 . 7033
- C3 and 2 . 505
- D3 and 0 . 7033
Correct answer
C. 3 and 2 . 505
Step-by-step solution
The expression for the Freundlich isotherm can be represented by the following equation x m = K p P 1 / n Taking log on both sides log x m = logk + 1 n logP On comparing with given equation of straight line, we get Y = 3 x + 2 . 505 ,   1 n = 3 ,   logK = 2 . 505 So, the answer is 3 and 2.505