JEE Main202330 Jan 2023Evening ShiftChemistrySurface ChemistryActual
The graph of log x m vs log p for an adsorption process is a straight line inclined at an angle of 45 ° with intercept equal to 0 . 6020 . The mass of gas adsorbed per unit mass of adsorbent at the pressure of 0 . 4 atm is _____ × 10 - 1 (Nearest integer) Given : log 2 = 0 . 3010
Correct answer
0
Step-by-step solution
The graphical representation of logarithmic form of Freundilich adsorption isotherm is as follows, The logarithmic form of Freundilich adsorption isotherm is log x m = logk + 1 n logP 1 n = tan 45 ° = 1 logk = 0 . 6020 = log 4 ⇒ K = 4 ∴     x m = K · P 1 / n x m = 4 0 . 4 = 1 . 6 x m = 1 . 6 = 16 × 10 - 1