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2 . 0   g of H 2   gas is adsorbed on 2 . 5   g of platinum powder at 300   K and 1 bar pressure. The volume of the gas adsorbed per gram of the adsorbent is mL (Given : R = 0 . 083   L bar K - 1   mol - 1 )

Correct answer

9960

Step-by-step solution

V H 2   =   nRT P V H 2 g = 2 2 0 . 083 300 1 ∴ Volume of H 2 g adsorbed on 2 . 5   Pt = 24 . 9   L ∴ Volume of H 2 g adsorbed on 1   g   of   Pt = 24 . 9 2 . 5 = 9 . 96   L = 9960   ml

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