When 200   mL of 0 . 2   M acetic acid is shaken with 0 . 6   g of wood charcoal, the final concentration of acetic acid after adsorption is 0 . 1   M . The mass of acetic acid adsorbed per gram of carbon is g .

Step-by-step solution

Mole of acetic acid absorbed (on 0.6 gram charcoal) = ( 0 . 2   X 200 ) 10 - 3   –   ( 0 . 1   X   200 ) 10 - 3 = 20   X   10 - 3 Weight of CH 3 COOH absorbed (on 0.6 gram charcoal) = ( 20   X 10 - 3   )   60   =   1200   X 10 - 3     gram   =   1 . 2   gram Mass of CH 3 COOH absorbed per gram= 1 . 2 0 . 6 = 2 grams