When 200mL of 0 . 2M acetic acid is shaken with 0 . 6g of wood...

Mole of acetic acid absorbed (on 0.6 gram charcoal) $= ( 0 . 2X200 ) {10}^{- 3} – ( 0 . 1X200 ) {10}^{- 3} = 20X{10}^{- 3}$

Weight of CH₃COOH absorbed (on 0.6 gram charcoal)$= ( 20X{10}^{- 3} ) 60 = 1200X{10}^{- 3}gram = 1 . 2gram$

Mass of CH₃COOH absorbed per gram=$\dfrac{1 . 2}{0 . 6} = 2$grams