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3 . 12   g of oxygen is adsorbed on 1 . 2   g of platinum metal. The volume of oxygen adsorbed per gram of the adsorbent at 1   atm and 300   K in L is R = 0 . 0821   L   atm   K - 1   mol - 1

Correct answer

2

Step-by-step solution

V = 3 . 12 32 × 0 . 0821 × 300 1 = 2 . 40   L ∵   1 . 2   gm adsorbs 2 . 40   L ∴   1   gm adsorbs 2   L

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