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JEE Main 20208 JanuaryMorning Shift
Exam
JEE Main
Year
2020
Date
8 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Surface Chemistry

JEE Main 2020 · 8 January · Morning Shift · Chemistry · Surface Chemistry

As per Hardy-Schulze formulation, the flocculation values of the...

As per Hardy-Schulze formulation, the flocculation values of the following for ferric hydroxide sol are in the order:

Options

  1. AK3[Fe(CN)6]<K2CrO4<KBr=KNO3=AlCl3{K}_{3}\left[Fe{\left(CN\right)}_{6}\right] < {K}_{2}Cr{O}_{4} < KBr = KN{O}_{3} = AlC{l}_{3}
  2. BK3[Fe(CN)6]<K2CrO4<AlCl3<KBr<KNO3{K}_{3}\left[Fe{\left(CN\right)}_{6}\right] < {K}_{2}Cr{O}_{4} < AlC{l}_{3} < KBr < KN{O}_{3}
  3. CAlCl3>K3[Fe(CN)6]>K2CrO4>KBr=KNO3AlC{l}_{3} > {K}_{3}\left[Fe{\left(CN\right)}_{6}\right] > {K}_{2}Cr{O}_{4} > KBr = KN{O}_{3}
  4. DK3[Fe(CN)6]>AlCl3>K2CrO4>KBr>KNO3{K}_{3}\left[Fe{\left(CN\right)}_{6}\right] > AlC{l}_{3} > {K}_{2}Cr{O}_{4} > KBr > KN{O}_{3}

Correct answer

A. K3[Fe(CN)6]<K2CrO4<KBr=KNO3=AlCl3{K}_{3}\left[Fe{\left(CN\right)}_{6}\right] < {K}_{2}Cr{O}_{4} < KBr = KN{O}_{3} = AlC{l}_{3}

Step-by-step solution

According to hardy-schultz rule,
Coagulation value or flocculation value ∝1Coagulationpower∝ \dfrac{1}{Coagulationpower}
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