Adsorption of a gas follows Freundlich adsorption isotherm. $x$ is the mass of the gas adsorbed on mass $m$ of the adsorbent. The plot of $log\dfrac{x}{m}$ vs $log$ \left(p\right) $is shown in the given graph.$ \dfrac{x}{m} is proportional to,

Question

Adsorption of a gas follows Freundlich adsorption isotherm.

x

is the mass of the gas adsorbed on mass

m

of the adsorbent. The plot of

log\dfrac{x}{m}

vs

log

\left(p\right)

is shown in the given graph.

\dfrac{x}{m} is proportional to,
Adsorption of a gas follows Freundlich adsorption isotherm. x is the mass of the gas adsorbed on mass m of the

Quantrex Academy · Accepted Answer

Correct answer: C. p ^ 2 / 3

According to Freundlich adsorption Isotherm,

\dfrac{x}{m} = k\left(P\right)\dfrac{1}{n}

log \dfrac{x}{m} = log k + \dfrac{1}{n}log p

y = mx + c; m = \dfrac{1}{n};

from the graph, \left(m = \dfrac{2}{3}\right)

<br />

\dfrac{x}{m} = k{\left(P\right)}^{\dfrac{2}{3}}

<br />

\dfrac{x}{m} ∝ {P}^{\dfrac{2}{3}}.

Adsorption of a gas follows Freundlich adsorption isotherm. x is...